How do you find out how much energy is used by an electric heating element?
How do you find out how much energy is used by an electric heating element?
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How do you find out how much energy is used by an electric heating element?
The heating element is connected to a 110V circut and a current of 3.2A flows through it. How much energy would be used in 5 hours?
Your help is appreciated
P = V*I
P = 110V * 3.2A = 352Volt*ampere = 352 Watts
5 hours = 18000 seconds
18000seconds*352joules/second= 6336 Kilojoule
So in 5 hours we have 6336 Kilojoules
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June 16th, 2010 at 9:34 am
P = V*I
P = 110V * 3.2A = 352Volt*ampere = 352 Watts
5 hours = 18000 seconds
18000seconds*352joules/second= 6336 Kilojoule
So in 5 hours we have 6336 Kilojoules
June 16th, 2010 at 9:34 am
W = IV = 3.2a x 110v = 352 watts
A watt is a joule per second
1w = 1J/s
So you have 352J/s x 5hrs x 3600s/hr
6,336,000 Joules
Enough to heat 100 liters of water by 15.15C.
……or 50 liters by 30.3C
……or 25 liters by 60.6C
And finally:
Enough to take 2.46 liters of water at room temperature and boil it. The actual boiling takes 7.2 x as much energy as the initial temperature rise from 25C to 100C.
June 16th, 2010 at 9:34 am
Power (Watts) = Current (Amps) x Voltage (Volts)
= 110 x 3.2 = 352Watts or 0.352 Kilowatts
Power consumption = Power (Kilowats) x Time (Hours)
= 0.352 x 5 = 1.76 KilowattHours (about 10p worth from my electricity supplier!)